# Line slope calculator 3x+7y=45

**Straight line given by points A[1; 6] and B[8; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.4286x+6.4286

**Canonical form of the line equation:**3x+7y-45 = 0

**Parametric form of the line equation:**

x = 7t+1

y = -3t+6 ; t ∈ R

**Slope:**m = -0.4286

**Slope angle of line: φ =**-23°11'55″ = -0.4049 rad

**X intercept:**x

_{0}= 15

**Y intercept:**y

_{0}= q = 6.4286

**Distance line from the origin:**d

_{0}= 5.9088

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; -3)

**Normal vector: n =**(3; 7)

**Midpoint of the segment AB: M =**[4.5; 4.5]

**Perpendicular Bisector equation:**7x-3y-18 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (8; 3) ; |OB| = 8.544**

**Scalar product OA .OB = 26**

**Angle ∠ AOB = 59°58'54″ = 1.0469 rad**